p + q = 1

__Problem__: 1 in 1700 US Caucasian newborns have cystic fibrosis. C for normal is dominant over c for cystic fibrosis.
Instructions

1. When counting the phenotypes in a population why is cc the most significant?
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2. What percent of the above population have cystic fibrosis (cc or q^{2})?
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3. From the above numbers you should be able to calculate the expectant frequencies of all the following (assuming a Hardy-Weinberg equilibirum):

__ALLELE FREQUENCY CALCULATIONS: __

Why calculate "q" first?
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(¦)c = q = ?
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Why is it now easy to find "p"?
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(¦)C = p = ?
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5. Now that you know that p =.976 and q = .024. The following genotypes can be found.

__GENOTYPE FREQUENCY CALCULATIONS__:

(^{2} = ?
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(¦)Cc -carriers of cystic fibrosis = 2pq = ?
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6. How many of the 1700 of the population are homozygous Normal?
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7. How many of the 1700 in the population are heterozygous (carrier)?
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8. It has been found that a carrier is better able to survive diseases with severe diarrhea. What would happen to the frequency of the "c" if there was a epidemic of cholera or other type of diarrhea producing disease?

Would "c" __Increase__?
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or would it __Decrease__?
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